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∫sin2u du
1/2 u - 1/4 sin (2u) + C
∫ cos2u du
1/2 u + 1/4 sin (2u) + C
1-sin2x =
cos2x =  
1 + tan2x =
sec2x =  
 sec2x - 1 =
tan2x =  
cot2x + 1 =  
csc2x =
csc2x - 1 =
cot2x =
sin (a + b) =
Sin a cos b + cos a sin b
cos (a + b) =
cos a cos b + sin a sin b
sin 2x =
2 sin x cos x
cos 2x =
cos2x - sin2x
cos2x =
1 + cos 2x __________       2
sin2x =
1 - cos 2x __________       2
cos2 (x/2) =
1 + cos x _________       2
sin2 (x/2) =
1 - cos x _________       2
∫ sec x dx =
ln l sec x + tan x l + C
∫ csc x dx =
ln l csc x - cot x l + C
d/dx ex =
ex
d/dx ln lxl =
1/x
d/dx (sin x) =
cos x
d/dx (cos x) =
-sin x
d/dx (tan x) =
sec2x
d/dx (cot x) =
-csc2x
d/dx (sec x) =
sec x tan x
d/dx (csc) =
-csc x cot x
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